{"id":214471,"date":"2023-01-03T10:42:22","date_gmt":"2023-01-03T09:42:22","guid":{"rendered":"https:\/\/educelec.com\/?page_id=214471"},"modified":"2026-01-01T14:19:44","modified_gmt":"2026-01-01T13:19:44","slug":"div-cour-tens","status":"publish","type":"page","link":"https:\/\/educelec.com\/en\/div-cour-tens\/","title":{"rendered":"Diviseur de tension et courant"},"content":{"rendered":"<p>[et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.16&Prime; global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb custom_margin=\u00a0\u00bb-50px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb custom_margin=\u00a0\u00bb|||-30px|false|false\u00a0\u00bb hover_enabled=\u00a0\u00bb0&Prime; global_colors_info=\u00a0\u00bb{}\u00a0\u00bb sticky_enabled=\u00a0\u00bb0&Prime;]<\/p>\n<p><a href=\"https:\/\/educelec.com\/en\/\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-216559\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2025\/12\/chap-300x209.png\" alt=\"\" width=\"17\" height=\"12\" \/><\/a><a href=\"https:\/\/educelec.com\/en\/\">Acceuil<\/a><a href=\"https:\/\/educelec.com\/en\/\">\u00a0&gt;<\/a> <a href=\"https:\/\/educelec.com\/en\/electricite\/\">Electricit\u00e9 &gt;<\/a> Ponts diviseurs<\/p>\n<p>[\/et_pb_text][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb text_font=\u00a0\u00bbAcme|700|||||||\u00a0\u00bb background_color=\u00a0\u00bb#88C4DD\u00a0\u00bb text_text_shadow_style=\u00a0\u00bbpreset1&Prime; text_text_shadow_blur_strength=\u00a0\u00bb2em\u00a0\u00bb text_text_shadow_color=\u00a0\u00bb#0047E0&Prime; locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb text_font_size__hover_enabled=\u00a0\u00bbon|desktop\u00a0\u00bb]<\/p>\n<blockquote>\n<h1 style=\"text-align: center;\"><strong>Exercices corrig\u00e9s<\/strong><\/h1>\n<h3 style=\"text-align: center;\"><strong>Diviseur de tension et courant <\/strong><\/h3>\n<\/blockquote>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 1<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4>Soit le circuit suivant:<\/h4>\n<h4><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exooooo1.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214530 alignnone size-full\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exooooo1.jpg\" alt=\"\" width=\"286\" height=\"255\" \/><\/a><br \/><span class=\"fontstyle0\">On donne : E = 12 V, R<\/span><span class=\"fontstyle0\">1 <\/span><span class=\"fontstyle0\">= 2,2 k\u03a9, R<\/span><span class=\"fontstyle0\">2 <\/span><span class=\"fontstyle0\">= 1k\u03a9 et R<\/span><span class=\"fontstyle0\">3 <\/span><span class=\"fontstyle0\">= 1,8k\u03a9<br \/><\/span><span class=\"fontstyle2\">1. <\/span><span class=\"fontstyle0\">Exprimer U<\/span><span class=\"fontstyle0\">1<\/span><span class=\"fontstyle0\">, U<\/span><span class=\"fontstyle0\">2 <\/span><span class=\"fontstyle0\">et U<\/span><span class=\"fontstyle0\">3 <\/span><span class=\"fontstyle0\">en fonction de E, R<\/span><span class=\"fontstyle0\">1<\/span><span class=\"fontstyle0\">, R<\/span><span class=\"fontstyle0\">2 <\/span><span class=\"fontstyle0\">et R<\/span><span class=\"fontstyle0\">3<\/span><span class=\"fontstyle0\">.<br \/><\/span><span class=\"fontstyle2\">2. <\/span><span class=\"fontstyle0\">Combien vaut la somme des 3 tensions U<\/span><span class=\"fontstyle0\">1<\/span><span class=\"fontstyle0\">+U<\/span><span class=\"fontstyle0\">2<\/span><span class=\"fontstyle0\">+U<\/span><span class=\"fontstyle0\">3 <\/span><span class=\"fontstyle0\">?<br \/><\/span><span class=\"fontstyle2\">3. <\/span><span class=\"fontstyle0\">Calculer la valeur la tension U<\/span><span class=\"fontstyle0\">3<\/span><span class=\"fontstyle0\">.<br \/><\/span><span class=\"fontstyle2\">4. <\/span><span class=\"fontstyle0\">On d\u00e9sire obtenir une tension U<\/span><span class=\"fontstyle0\">3 <\/span><span class=\"fontstyle0\">= 2 V, sans modifier les valeurs de R<\/span><span class=\"fontstyle0\">1 <\/span><span class=\"fontstyle0\">et R<\/span><span class=\"fontstyle0\">3<\/span><span class=\"fontstyle0\">.Quelle doit \u00eatre la valeur de R<\/span><span class=\"fontstyle0\">2 <\/span><span class=\"fontstyle0\">?<\/span><\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.19.1&Prime; custom_margin=\u00a0\u00bb-100px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 2<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4><span class=\"fontstyle0\">Soit le circuit suivant :<\/span><\/h4>\n<p><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/10\/exo-div-2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-215259 alignnone size-medium\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/10\/exo-div-2-300x111.png\" alt=\"\" width=\"300\" height=\"111\" \/><\/a><\/p>\n<h4><span class=\"fontstyle0\">1. Pour R1=R3=R5=R6=R et R2=R4=2R <\/span><\/h4>\n<h4><span class=\"fontstyle2\">Calculer la r\u00e9sistance \u00e9quivalente \u00e0 tout le r\u00e9seau, vue entre les points A et M.<br \/><\/span><\/h4>\n<h4><span class=\"fontstyle0\">2.\u00a0<\/span><span class=\"fontstyle2\">Calculer les tensions V<\/span><span class=\"fontstyle2\">BM<\/span><span class=\"fontstyle2\">, V<\/span><span class=\"fontstyle2\">CM <\/span><span class=\"fontstyle2\">et V<\/span><span class=\"fontstyle2\">DM<\/span><span class=\"fontstyle2\">.<\/span><\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=\u00a0\u00bb1&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb custom_margin=\u00a0\u00bb-100px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 3<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4>Soit le circuit suivant :<\/h4>\n<p><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2022\/12\/ex8.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214386 alignnone\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2022\/12\/ex8-300x113.png\" alt=\"\" width=\"476\" height=\"179\" \/><\/a><\/p>\n<h4>1. Calculer la r\u00e9sistance \u00e9quivalente <strong>R\u00e9q<\/strong> de ce circuit entre<strong> A<\/strong> et <strong>B<\/strong>.<\/h4>\n<h4>2. Calculer l\u2019intensit\u00e9 du courant<strong> I<\/strong> fourni par la source <strong>E<\/strong>.<\/h4>\n<h4>3. Calculer la tension <strong>U1<\/strong> aux bornes de <strong>R1<\/strong>.<\/h4>\n<h4>4. Calculer la tension <strong>U2<\/strong> aux bornes de <strong>R2<\/strong>.<\/h4>\n<h4>5. Calculer la tension <strong>U3<\/strong> aux bornes de <strong>R3<\/strong>.<\/h4>\n<h4>6. Calculer la tension <strong>U4<\/strong> aux bornes de <strong>R5<\/strong>.<\/h4>\n<h4>7. Calculer la tension <strong>U5<\/strong> aux bornes de<\/h4>\n<h4>8.Calculer les courants qui circulent dans chaque branche (<strong>I1<\/strong>, <strong>I3<\/strong> et <strong>I4<\/strong>).<\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>","protected":false},"excerpt":{"rendered":"<p>Acceuil\u00a0&gt; Electricit\u00e9 &gt; Ponts diviseursExercices corrig\u00e9s Diviseur de tension et courant Exercice N\u00b0 1 Soit le circuit suivant: On donne : E = 12 V, R1 = 2,2 k\u03a9, R2 = 1k\u03a9 et R3 = 1,8k\u03a91. Exprimer U1, U2 et U3 en fonction de E, R1, R2 et R3.2. Combien vaut la somme des 3 [&hellip;]<\/p>","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"","_et_gb_content_width":"","om_disable_all_campaigns":false,"_uf_show_specific_survey":0,"_uf_disable_surveys":false,"footnotes":""},"class_list":["post-214471","page","type-page","status-publish","hentry"],"aioseo_notices":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.6 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Diviseur de tension et courant - Exercices et Solutions en Electricit\u00e9, Electronique, Electrotechnique et Automatisme industrielle<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/educelec.com\/en\/div-cour-tens\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Diviseur de tension et courant - Exercices et Solutions en Electricit\u00e9, Electronique, Electrotechnique et Automatisme industrielle\" \/>\n<meta property=\"og:description\" content=\"Acceuil\u00a0&gt; Electricit\u00e9 &gt; Ponts diviseursExercices corrig\u00e9s Diviseur de tension et courant Exercice N\u00b0 1 Soit le circuit suivant: On donne : E = 12 V, R1 = 2,2 k\u03a9, R2 = 1k\u03a9 et R3 = 1,8k\u03a91. Exprimer U1, U2 et U3 en fonction de E, R1, R2 et R3.2. 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Exprimer U1, U2 et U3 en fonction de E, R1, R2 et R3.2. 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