{"id":214480,"date":"2023-01-03T10:47:20","date_gmt":"2023-01-03T09:47:20","guid":{"rendered":"https:\/\/educelec.com\/?page_id=214480"},"modified":"2026-01-01T14:21:47","modified_gmt":"2026-01-01T13:21:47","slug":"loi-kirch","status":"publish","type":"page","link":"https:\/\/educelec.com\/en\/loi-kirch\/","title":{"rendered":"Loi de kirchhoff"},"content":{"rendered":"<p>[et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.16&Prime; global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb custom_margin=\u00a0\u00bb-50px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb custom_margin=\u00a0\u00bb|||-30px|false|false\u00a0\u00bb hover_enabled=\u00a0\u00bb0&Prime; global_colors_info=\u00a0\u00bb{}\u00a0\u00bb sticky_enabled=\u00a0\u00bb0&Prime;]<\/p>\n<p><a href=\"https:\/\/educelec.com\/en\/\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-216559\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2025\/12\/chap-300x209.png\" alt=\"\" width=\"17\" height=\"12\" \/><\/a><a href=\"https:\/\/educelec.com\/en\/\">Acceuil<\/a><a href=\"https:\/\/educelec.com\/en\/\"> &gt;<\/a> <a href=\"https:\/\/educelec.com\/en\/electricite\/\">Electricit\u00e9 &gt; <\/a><strong>Lois de kirchhoff<\/strong><\/p>\n<p>[\/et_pb_text][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb text_font=\u00a0\u00bbAcme|700|||||||\u00a0\u00bb background_color=\u00a0\u00bb#88C4DD\u00a0\u00bb text_text_shadow_style=\u00a0\u00bbpreset1&Prime; text_text_shadow_blur_strength=\u00a0\u00bb2em\u00a0\u00bb text_text_shadow_color=\u00a0\u00bb#0047E0&Prime; locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb text_font_size__hover_enabled=\u00a0\u00bbon|desktop\u00a0\u00bb]<\/p>\n<blockquote>\n<h1 style=\"text-align: center;\"><strong>Exercices corrig\u00e9s<\/strong><\/h1>\n<h3 style=\"text-align: center;\"><strong>Lois de kirchhoff<\/strong><\/h3>\n<\/blockquote>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 1<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4><strong>Soit le circuit suivant\u00a0:<\/strong><\/h4>\n<h4>\u00a0<\/h4>\n<h4><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo1-Kirch.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214606 alignnone size-medium\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo1-Kirch-300x177.png\" alt=\"\" width=\"300\" height=\"177\" srcset=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo1-Kirch-300x177.png 300w, https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo1-Kirch.png 309w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/h4>\n<h4>\u00a0<\/h4>\n<h4>On donne : E1 = 12 V ; E2 = 5 V ; R1=R2= 1 \u2126 ; R3= 4 \u2126 ; I1 = 2 A<\/h4>\n<h4>1. Calculer la tension aux borne de R1.<\/h4>\n<h4>2. Calculer la valeur de R4.<\/h4>\n<h4>3. Calculer les puissances dissip\u00e9es dans R1 et R2.<\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.19.1&Prime; custom_margin=\u00a0\u00bb-100px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 2<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4><strong>Soit le circuit suivant\u00a0:<\/strong><\/h4>\n<p><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214609 alignnone size-medium\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch-300x189.png\" alt=\"\" width=\"300\" height=\"189\" srcset=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch-300x189.png 300w, https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch.png 385w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<h4><strong>On donne :\u00a0 R1 = 1k\u03a9,\u00a0 R2 = 2k\u03a9,\u00a0 R3 = 4k\u03a9,\u00a0 R4 = R5 = 3k\u03a9, la tension aux bornes de la r\u00e9sistance R2, UR2 = 4V, et le courant I3 = 2mA. <\/strong><\/h4>\n<h4><strong>Calculer E et R <\/strong><\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.19.1&Prime; custom_margin=\u00a0\u00bb-100px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 3<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4><strong>Soit le circuit suivant\u00a0:<\/strong><\/h4>\n<h4><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo3-Kirch.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214612 alignnone size-full\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo3-Kirch.png\" alt=\"\" width=\"254\" height=\"220\" \/><\/a><\/h4>\n<h4>On donne\u00a0: E1 = 12 V\u00a0; E2 = 8 V\u00a0; E3 = 6 V\u00a0; R1=R2= 2 \u2126\u00a0; R3= 3 \u2126.<\/h4>\n<h4>\u00b7\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Calculer la diff\u00e9rence de potentiel dans chaque r\u00e9sistance<\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_toggle title=\u00a0\u00bbToucher pour afficher la solution\u00a0\u00bb _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb title_font_size=\u00a0\u00bb13px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<p>&nbsp;<\/p>\n<p><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2022\/12\/arri.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214149 alignnone size-medium\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2022\/12\/arri-300x211.png\" alt=\"\" width=\"300\" height=\"211\" \/><\/a><\/p>\n<p>kjsnoangownsrgqaknqreqlknrhl\u00f6wekflkj<\/p>\n<p>[\/et_pb_toggle][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.19.1&Prime; custom_margin=\u00a0\u00bb-100px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 4<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<h4><strong>Soit le circuit suivant\u00a0:<\/strong><\/h4>\n<p><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214609 alignnone size-medium\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch-300x189.png\" alt=\"\" width=\"300\" height=\"189\" srcset=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch-300x189.png 300w, https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo2-Kirch.png 385w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<h4><strong>On donne :\u00a0 R1 = 1k\u03a9,\u00a0 R2 = 2k\u03a9,\u00a0 R3 = 4k\u03a9,\u00a0 R4 = R5 = 3k\u03a9, la tension aux bornes de la r\u00e9sistance R2, UR2 = 4V, et le courant I3 = 2mA. <\/strong><\/h4>\n<h4><strong>Calculer E et R <\/strong><\/h4>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section][et_pb_section fb_built=\u00a0\u00bb1&Prime; admin_label=\u00a0\u00bbsection\u00a0\u00bb _builder_version=\u00a0\u00bb4.19.1&Prime; custom_margin=\u00a0\u00bb-100px||||false|false\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb background_color=\u00a0\u00bb#38D7FF\u00a0\u00bb min_height=\u00a0\u00bb40px\u00a0\u00bb height=\u00a0\u00bb40px\u00a0\u00bb custom_padding=\u00a0\u00bb7px|||18px|false|false\u00a0\u00bb border_width_all=\u00a0\u00bb2px\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<ul>\n<li>\n<h3><strong>Exercice N\u00b0 5<\/strong><\/h3>\n<\/li>\n<\/ul>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][et_pb_row _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb locked=\u00a0\u00bboff\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_column type=\u00a0\u00bb4_4&Prime; _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb][et_pb_text _builder_version=\u00a0\u00bb4.19.1&Prime; _module_preset=\u00a0\u00bbdefault\u00a0\u00bb global_colors_info=\u00a0\u00bb{}\u00a0\u00bb]<\/p>\n<p><strong>Soit le circuit suivant\u00a0:<\/strong><\/p>\n<p><a href=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo4-Kirch.png\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-214615 alignnone size-medium\" src=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo4-Kirch-300x185.png\" alt=\"\" width=\"300\" height=\"185\" srcset=\"https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo4-Kirch-300x185.png 300w, https:\/\/educelec.com\/wp-content\/uploads\/2023\/01\/exo4-Kirch.png 310w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p><strong>I3 = 2mA, E3 = 18 V\u00a0; R1= 1 K\u2126\u00a0; R3= 1,5 K\u2126 U<\/strong><strong>CD <\/strong><strong>= 7 V<\/strong><\/p>\n<p><strong>Calculer la valeur de la r\u00e9sistance R2. <\/strong><\/p>\n<p>[\/et_pb_text][\/et_pb_column][\/et_pb_row][\/et_pb_section]<\/p>","protected":false},"excerpt":{"rendered":"<p>Acceuil &gt; Electricit\u00e9 &gt; Lois de kirchhoffExercices corrig\u00e9s Lois de kirchhoff Exercice N\u00b0 1 Soit le circuit suivant\u00a0: \u00a0 \u00a0 On donne : E1 = 12 V ; E2 = 5 V ; R1=R2= 1 \u2126 ; R3= 4 \u2126 ; I1 = 2 A 1. Calculer la tension aux borne de R1. 2. Calculer [&hellip;]<\/p>","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_et_pb_use_builder":"on","_et_pb_old_content":"","_et_gb_content_width":"","om_disable_all_campaigns":false,"_uf_show_specific_survey":0,"_uf_disable_surveys":false,"footnotes":""},"class_list":["post-214480","page","type-page","status-publish","hentry"],"aioseo_notices":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.6 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Loi de kirchhoff - Exercices et Solutions en Electricit\u00e9, Electronique, Electrotechnique et Automatisme industrielle<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/educelec.com\/en\/loi-kirch\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Loi de kirchhoff - Exercices et Solutions en Electricit\u00e9, Electronique, Electrotechnique et Automatisme industrielle\" \/>\n<meta property=\"og:description\" content=\"Acceuil &gt; Electricit\u00e9 &gt; Lois de kirchhoffExercices corrig\u00e9s Lois de kirchhoff Exercice N\u00b0 1 Soit le circuit suivant\u00a0: \u00a0 \u00a0 On donne : E1 = 12 V ; E2 = 5 V ; R1=R2= 1 \u2126 ; R3= 4 \u2126 ; I1 = 2 A 1. 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